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15 November, 08:27

A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of the horizontal and vertical components of this vector?

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  1. 15 November, 10:51
    0
    The horizontal component is 37.74 N to east

    The vertical component is 16.02 N to North

    Explanation:

    Any slant vector has two components

    → Horizontal component = R cos Ф

    → Vertical component = R sin Ф

    → R is the magnitude of the vector

    → Ф is the direction of the vector with positive part of the horizontal axis

    A slanted vector has a magnitude of 41 N and is at an angle of 23

    degrees north of east

    23° north of east means the angle between the vector and the

    east direction is 23° (east is the positive horizontal direction)

    That means R is 41 N and Ф is 23°

    → R = 41 N, Ф = 23°

    → The horizontal component = 41 * cos (23) = 37.74 N east

    → The vertical component = 41 * sin (23) = 16.02 N North

    The horizontal component is 37.74 N to east

    The vertical component is 16.02 N to North
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