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5 November, 19:38

A water drop of mass 20g falls to the ground with a velocity of 8m/s from a height of 20m. what is the air resistance force acting on the water drop?

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  1. 5 November, 22:31
    0
    0.164 N

    Explanation:

    Newton's second law: sum of the forces equals mass times acceleration.

    ∑F = ma

    F - mg = ma

    a = (F - mg) / m

    In real life, air resistance is a function of velocity. But we will assume that it is constant.

    Given:

    y₀ = 20 m

    y = 0 m

    v₀ = 0 m/s

    v = - 8 m/s

    Find: a

    v² = v₀² + 2a (y - y₀)

    (-8 m/s) ² = (0 m/s) ² + 2a (0 m - 20 m)

    a = - 1.6 m/s²

    Therefore:

    -1.6 m/s² = (F - 0.020 kg * 9.8 m/s²) / 0.020 kg

    F = 0.164 N

    Round as needed.
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