Ask Question
21 September, 20:06

A 50 mL graduated cylinder contains 25.0 mL of water. A 42.5040 g piece of gold is placed in the graduated cylinder and the water level rises to 27.2 mL. What is the density of the piece of gold?

+3
Answers (1)
  1. 21 September, 23:52
    0
    19320 kg/m³

    Explanation:

    density: This can be defined as the ratio of the mass of a body to its volume. The S. I unit of Density is kg/m³.

    The formula of density is given as,

    D = m/v ... Equation 1.

    Where D = Density of the gold, m = mass of the gold, v = volume of the gold.

    Note: From Archimedes's Principle, the piece of gold displace an amount of water that is equal to it's volume.

    Amount of water displace = 27.2 - 25 = 2.2 mL.

    Given: m = 42.504 g = 0.042504 kg, v = 2.2 mL = (2.2/10⁶) m³ = 0.0000022 m³

    Substitute into equation 1

    D = 0.042504/0.0000022

    D = 19320 kg/m³

    Hence the density of the piece of gold = 19320 kg/m³
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 50 mL graduated cylinder contains 25.0 mL of water. A 42.5040 g piece of gold is placed in the graduated cylinder and the water level ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers