Ask Question
19 April, 08:20

Two sinusoidal waves travel along the same string. They have the same wavelength and frequency. Their amplitudes are ym1 = 2.5 mm and ym2 = 4.5 mm, and their phases are π / 4 rad and π / 2 rad, respectively. What are the amplitude and phase of the resultant wave?

+1
Answers (1)
  1. 19 April, 11:24
    0
    0.5 m

    Explanation:

    Givens:

    ym1 = 2.5 mm

    ym2 = 4.5 mm

    Ф_1=π / 4

    Ф_2=π / 2

    We have 2 ways to solve this problem. The first one given that the 2 waves have the frequency then we know that the resultant wave amplitude is

    Ym = (ym1 + ym2) cos (Ф_2/2)

    By substitution we have

    Ym = (0.025 + 0.045) cos (π/4) = 0.496 m

    The second one is it treat them as Phasors where the phase between them is Ф_2=π / 2 Therefore

    Ym^2 = (ym1^2+ym2^2)

    So we have Ym=√0.025^2+0.045^2

    = 0.5 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Two sinusoidal waves travel along the same string. They have the same wavelength and frequency. Their amplitudes are ym1 = 2.5 mm and ym2 = ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers