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30 August, 12:23

Two identical conducting spheres each having a radius of 0.500 cm are connected by a light, 1.90-m-long conducting wire. A charge of 41.0 μC is placed on one of the conductors. Assume the surface distribution of charge on each sphere is uniform. Determine the tension in the wire.

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  1. 30 August, 15:29
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    Answer: 4.19 N

    Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.

    As the wire is a conductor the spheres are at same potential so we have:

    V1=V2

    V1=k*Q1/r1 and V2=k*Q2/r2

    where r1=r2, then

    Q1=Q2

    so the electric force is given by:

    F=k*Q^2/d^2 where d is the distance between the spheres.

    Finally replacing the values, we have

    F=9*10^9 (41*10^-6) ^2 / (1.9) ^2 = 4.19 N
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