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9 January, 01:25

Consider a simple parallel-plate capacitor whose plates are

given equal and opposite charges and are separated by a

distance d. Suppose the plates are pulled apart until they are

separated by a distance D > d. The electrostatic energy

stored in the capacitor is

1. greater than

2. the same as

3. smaller than

and what is also the ans before the plates were pulled apart

+2
Answers (1)
  1. 9 January, 05:07
    0
    The correct answer is 3

    Explanation:

    The capacitance in a capacitor is

    C = ε₀ A / d

    When we separate the capacitors the capacitance decreases

    Let's look for capacitance

    C₀ = ε₀ A / d

    C = ε₀ A / D

    The relationship between the two capacitances is

    C / C₀ = d / D

    The energy stored in a capacitor is

    U = ½ C ΔV²

    If we maintain the same potential difference, the stored energy decreases if the capacitance decreases

    The correct answer is 3

    The relationship between the two energies is

    U₀ = ½ ε₀ A / d ΔV²

    U = ½ eo A / D ΔV²

    U / U₀ = d/D
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