A car is traveling at 33.0 m/s when the driver uses the brakes to slow down to 29.0 m/s in 2.50 seconds. How many meters will it travel during that time?

Distance traveled during that time is 77.5 m

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 33 m/s

Final velocity, v = 29 m/s

Time, t = 2.50 s

Substituting

v = u + at

29 = 33 + a x 2.50

a = - 1.6 m/s²

We have equation of motion v² = u² + 2as

Initial velocity, u = 33 m/s

Acceleration, a = - 1.6 m/s²

Final velocity, v = 29 m/s

Substituting

v² = u² + 2as

29² = 33² + 2 x - 1.6 x s

s = 77.5 m

Distance traveled during that time is 77.5 m