In a baseball game, a batter hits the 0.150-kg ball straight back at the pitcher at 180 km/h.

If the ball is traveling at 160 km/h just before it reaches the bat, what is the magnitude of the average force exerted by the bat on it if the collision lasts 5.0 ms?

F = ?

Answer: F = 0.17N

Explanation: From the Newton second law of motion.

F = m (v-u) / t.

V=180km/hr = 180*1000/3600 = 50m/s

U = 160km/hr = 160*1000/3600 = 44.44m/s

t = 5secs

F=m (v-u) / t

F = 0.150 (50-44.44) / 5

F=0.150*5.56/5

F = 0.835/5

F = 0.17N rounded to two decimal places.