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20 October, 12:56

A refrigerator uses 40.0 J of work to extract heat from a heat reservoir at 0.00°C. If the coefficient of performance of the refrigerator is 2.10, then how much heat is discharged out of the refrigerator at a higher temperature?

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  1. 20 October, 15:28
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    Heat discharged out of the refrigerator = 84 J

    Explanation:

    Coefficient of performance:

    Ratio of work output to the amount of work or energy input. Coefficient of performance used generally as a measure of the energy ratio of air conditioners, space heaters. etc

    Generally, Coefficient of performance (COP) = Wok output / work input

    Work output = Heat discharged out of the refrigerator, Work input = Electrical energy used by the refrigerator.

    ∴ Coefficient of performance (COP) = Heat discharged out of the refrigerator / Electrical energy used by the refrigerator.

    The energy used by the refrigerator = 40.0 J and

    Coefficient of performance (COP) = 2.10.

    Heat discharged out of the refrigerator = 40 * 2.10 = 84 J

    ∴ Heat discharged out of the refrigerator = 84 J
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