Two parallel conducting plates that are in deep space are brought to a potential difference of 3000 V, and a small pellet of mass 2.60 mg carrying a charge of 6.00 * 10-7 C accelerates from rest from the positive plate. With what speed will it reach the other plate?

Question

Asia Mendez

2 November, 08:30

+4

Answers (1)

Know the Answer?

Sariah · Answer 1

qU = Ek = ½mv²

6.00 * 10^-7 * 3000 = ½ * 0.0026 * v²

v² = 0.7222167

v = 0.8498 m/s