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25 February, 10:29

A pair of oppositely charged parallel plates is separated by 5.38 mm. A potential difference of 623 V exists between the plates. What is the strength of the electric field between the plates? The fundamental charge is 1.602 * 10-19. Answer in units of V/m.

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  1. 25 February, 11:20
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    115799.256V/m

    Explanation:

    Given V = 623v, d = 5.38mm = 0.00538m

    Strength of electric field E = V/d

    E = 623/0.00538

    = 115799.256V/m
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