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10 February, 01:57

Now imagine that the coil is subjected to a series of experiments, that we will label 1, 2, etc., for clarity. At the beginning of both experiments 1 and 2, the magnetic field is initially 3.0 T. In experiment 1, the magnetic field is changed in 2.0 ms from 3.0 T to 6.0 T. In experiment 2, the magnetic field is changed in 2.0 ms from 3.0 T to 20.0 T. What is the ratio of the average emf observed in each case, EMF1 / EMF2?

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  1. 10 February, 02:34
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    EMF1/EMF2 = 3/17 = 0.176

    Explanation:

    Experiment 1:

    B₁ = 3.0 T

    B₂ = 6.0 T

    dt = 2 ms

    dB = B₂ - B₁ = 6 T-3 T

    dB = 3 T

    Now

    ∅ = B*A cosθ (A is area of the coil)

    d∅ = dB*A cosθ

    d∅ = 3*A cosθ

    Average emf

    ε₁ = d∅/dt

    ε₁=3*A cosθ / 2*10^-3

    ε₁=1500*A*cosθ

    Experiment 2:

    B₁ = 3.0 T

    B₂ = 20.0 T

    dt = 2 ms

    dB = B₂ - B₁ = 20 T-3 T

    dB = 17 T

    Now

    ∅ = B*A cosθ (A is area of the coil)

    d∅ = dB*A cosθ

    d∅ = 17*A cosθ

    Average emf

    ε₂ = d∅/dt

    ε₂=17*A cosθ / 2*10^-3

    ε₂=8500*A*cosθ

    Ratio of average emf:

    EMF1/EMF2 = ε₁/ε₂ = (1500*A*cosθ) / (8500*A*cosθ)

    EMF1/EMF2 = 1500/8500

    EMF1/EMF2 = 3/17 = 0.176
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