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16 October, 23:12

1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?

Use energy equations first, then prove it with projectiles math.

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  1. 17 October, 00:43
    0
    14.2 m

    Explanation:

    Using conservation of energy:

    PE at top = KE at bottom

    mgh = ½ mv²

    h = v² / (2g)

    h = (16.7 m/s) ² / (2 * 9.8 m/s²)

    h = 14.2 m

    Using kinematics:

    Given:

    v₀ = 16.7 m/s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: Δy

    v² = v₀² + 2aΔy

    (0 m/s) ² = (16.7 m/s) ² + 2 (-9.8 m/s²) Δy

    Δy = 14.2 m
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