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11 May, 06:10

A 0.500 kg block of lead is heated from 295 K to 350. K. How much heat was absorbed by the lead? (express your answer to the nearest joule

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  1. 11 May, 07:47
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    The amount of energy needed to change the temperature of a certain supstance is given in the equation:

    Q = c • m • ∆T

    -Q is the amount of energy in Joules

    -c is the specific heat capacity, a constant value for each supstance that shows amount of energy needed to raise the temperature of 1 g of a supstance by 1 K. Its unis is J/g•K (for lead, c=0.129J/g•K)

    -m is the mass of the given supstance in grams

    -∆T is the change in the temperature in Kelvins. In this case it's 350-295=55K

    So, now, let's calculate:

    Q = 0.129J/g•K • 500g • 55K

    Q = 3,547.5 J

    Rounded to the nearest whole number that is 3,548 Joules
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