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3 January, 04:40

uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is the potential difference between the plates?

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  1. 3 January, 07:17
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    potential difference V = 300 volts

    Explanation:

    Given:

    d = 2.0 cm = 0.02m

    E = 15 kN/C = 15 * 10³ N/C

    For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely proportional to distance between the plates.

    E = V/d

    ⇒ V = E*d = 15 * 10³ N/C * 0.02 m = 300 volts (∴1 Nm/C = 1 J/C = 1 volts)
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