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3 May, 22:15

A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?

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Answers (1)
  1. 4 May, 00:02
    0
    The answer to your question is:

    Explanation:

    Data

    mass = 4.33 kg

    E = 41.7 J

    v = ?

    Formula

    Ke = (1/2) mv²

    Clear v from the equation

    v = √2ke/m

    Substitution

    v = √2 (41.7) / 4.33

    v = 19.26 m/s Result
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