A hot rod can accelerate from 0 to 60 km/h in 5.4 s.

(a) What is its average acceleration, in m/s2, during this time?

(b) How far will it travel during the 5.4 s, assuming its acceleration is constant?

(c) From rest, how much time would it require to go a distance of 0.25 km if its acceleration could be maintained at the value in (a) ?

a) Acceleration is 3.09 m/s²b) Distance traveled is 45.05 mc) Time taken to travel 250 m is 12.72 s

Explanation:

a) We have equation of motion v = u + at

Initial velocity, u = 0 km/hr = 0 m/s

Final velocity, v = 60 km/hr = 16.67 m/s

Time, t = 5.4 s

Substituting

v = u + at

16.67 = 0 + a x 5.4

a = 3.09 m/s²

Acceleration is 3.09 m/s²

b) We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 3.09 m/s²

Time, t = 5.4 s

Substituting

s = ut + 0.5 at²

s = 0 x 5.4 + 0.5 x 3.09 x 5.4²

s = 45.05 m

Distance traveled is 45.05 m

c) We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 3.09 m/s²

Displacement, s = 0.25 km = 250 m

Substituting

s = ut + 0.5 at²

250 = 0 x t + 0.5 x 3.09 xt²

t = 12.72 s

Time taken to travel 250 m is 12.72 s