Ask Question
6 September, 09:37

A 22.6-kg box is being pushed from the bottom to the top of a frictionless ramp. When the box is pushed at a constant velocity, the nonconservative pushing force does 58.0 J of work. How much work is done by the pushing force when the box starts from rest at the bottom and reaches the top of the same ramp with a speed of 1.50 m/s?

+2
Answers (1)
  1. 6 September, 09:50
    0
    work done = 79.825 J

    Explanation:

    given,

    mass of box = 22.6 Kg

    energy = 58 J

    speed = 1.5 m/s

    for box and the earth system the only external force is the pushing force

    work done by external force = change of energy of the system

    U = work done - K

    box is moving with constant velocity hence no change in kinetic energy.

    so, K is equal to zero.

    U = work done

    U = 58.0 J

    work done by pushing force = K + U

    now, work done when box reaches to the speed of 1.5 m/s

    work done = final kinetic energy - initial kinetic energy + U

    work done = 0.5 m v² - 0 + U

    work done = 0.5 x 19.4 x 1.5² + 58.0

    work done = 79.825 J
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 22.6-kg box is being pushed from the bottom to the top of a frictionless ramp. When the box is pushed at a constant velocity, the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers