Ask Question
28 August, 00:55

f 720-nm and 620-nm light passes through two slits 0.68 mm apart, how far apart are the second-order fringes for these two wavelengths on a screen 1.0 m away

+1
Answers (1)
  1. 28 August, 01:09
    0
    0.0003 m = 0.3 mm

    Explanation:

    For constructive interference in the Young's experiment.

    The position of the mth fringe from the central fringe is given by

    y = L (mλ/d)

    λ = wavelength = 720 nm = 720 * 10⁻⁹ m

    L = distance between slits and screen respectively = 1.0 m

    d = separation of slits = 0.68 mm = 0.68 * 10⁻³ m

    m = 2

    y = 1 (2 * 720 * 10⁻⁹ / (0.68 * 10⁻³) = 0.00212 m = 2.12 mm

    For the 620 nm light,

    y = 1 (2 * 620 * 10⁻⁹ / (0.68 * 10⁻³) = 0.00182 m = 1.82 mm

    Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “f 720-nm and 620-nm light passes through two slits 0.68 mm apart, how far apart are the second-order fringes for these two wavelengths on a ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers