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21 February, 08:13

A student creates a circuit that consists of a single battery and four resistors that are arranged as shown. How much energy is dissipated by the 2 Ω resistor after 120 s if the total current drawn from the battery is 5 A?

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  1. 21 February, 11:29
    0
    6000JOules

    Explanation:

    My friend this is quite easy.

    There is an equation.

    The energy is also presumed as heat.

    To calculate the heat in a circuit or the energy the equation is H=I (square) RT

    Heat = square of current x resistance x time

    Here I=5a.

    R=2 ohm

    T=120s

    H = 5x5x2x120=6000J

    I hope this satisfies you.

    If you have any questions ask me.

    I hope u will follow me and make this the brainliest answer.

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