A 75-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20.

What horizontal force must be applied to the box to cause it to start sliding along the surface?

Question

Physics

Trevon

3 December, 16:08

A 75-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20.

What horizontal force must be applied to the box to cause it to start sliding along the surface?

+3

Answers (1)

Know the Answer?

Armani Huerta · Answer 1

220 N

Explanation:

To get the box to start moving, you must overcome the static friction.

F = N μs

F = mg μs

F = (75 kg) (9.8 m/s²) (0.30)

F = 220 N

A 75-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20.What horizontal force must be applied to the box to cause it to start sliding along the surface?

A 75-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20.

What horizontal force must be applied to the box to cause it to start sliding along the surface?