During each heartbeat, about 80 g of blood is pumped into the aorta in approximately 0.2 s. During this time, the blood is accelerated from rest to about 1 m/s. Part A) What is the average force on the blood during this time? A. 0.08 NB. 0.4 NC. 400 ND. 0.2 NPart B) What is the acceleration of the blood during this time? A. 0.08 m/s^2B. 10 m/s^2C. 5 m/s^2D. 1 m/s^2

Part A)

B. 0.4 N

Part B)

C. 5 m/s²

Explanation:

Part A)

Force: This can be defined as the product of mass and acceleration

F = ma ... Equation 1

Where F = force of the blood, m = mass of the blood, a = acceleration of the blood.

Also,

a = (v-u) / t ... Equation 2

Substituting equation 2 into equation 1

F = m (v-u) / t ... Equation 3

Where v = initial velocity, u = final velocity, t = time.

Given: v = 1 m/s u = 0 m/s (from rest) t = 0.2 s, m = 80 g = 0.08 kg.

Substitute into equation 3

F = 0.08 (1-0) / 0.2

F = 0.08/0.2

F = 0.4 N

The right option is B. 0.4 N

Part B)

Acceleration: This is defined as the rate of change of velocity.

a = (v-u) / t

Where a = acceleration, v = final velocity, u = initial velocity, t = time.

Given: v = 1 m/s u = 0 m/s (from rest), t = 0.2 s.

Substitute into the equation above,

a = (1-0) / 0.2

a = 1/0.2

a = 5 m/s²

The right option is C. 5 m/s²