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21 January, 13:11

A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic friction is 0.19, what is the magnitude of the acceleration, in m/s2, of the box down the slope?

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  1. 21 January, 15:51
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    a = 4.72 m/s²

    Explanation:

    given,

    mass of the box (m) = 6 Kg

    angle of inclination (θ) = 39°

    coefficient of kinetic friction (μ) = 0.19

    magnitude of acceleration = ?

    box is sliding downward so,

    F - f = m a

    f is the friction force

    m g sinθ - μ N = ma

    m g sinθ - μ m g cos θ = ma

    a = g sinθ - μ g cos θ

    a = 9.8 x sin 39° - 0.19 x 9.8 x cos 39°

    a = 4.72 m/s²

    the magnitude of acceleration of the box down the slope is a = 4.72 m/s²
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