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25 November, 17:17

A test charge of 0.002 C experiences a force of 0.50 N on it is placed in an electric field. Find the intensity of the electric field

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  1. 25 November, 20:38
    0
    250 N/C

    Explanation:

    E=F/q=0,5N/0,002C=250N/C
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