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29 August, 15:26

The average human has a density of 945 kg/m3 after inhaling and 1020 kg/m3 after exhaling. (a) Without making any swimming movements, what percentage of the human body would be above the surface in the Dead Sea (a body of water with a density of about 1230 kg/m3) in each of these cases?

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  1. 29 August, 17:21
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    20% of the human body float above the surface in the dead sea.

    Explanation:

    Given data,

    The human density after inhaling, d₁ = 945 kg/m³

    The human density after exhaling, d₂ = 1020 kg/m³

    Therefore the average human density, d = 982.5 kg/m³

    The density of the dead sea, D = 1230 kg/m³

    The percentage of density of human body to the dead sea is,

    P % = (982.5 / 1230) x 100 %

    = 80 %

    Therefore, the human body has 80% of dead sea density.

    Hence, 20% of the human body float above the surface in the dead sea.
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