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14 November, 20:08

A wire carries a current of 6.91 A in a direction that makes an angle of 19◦ with the direction of a magnetic field of strength 0.289 T. Find the magnetic force on a 6.7 m length of the wire. Answer in units of N.

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  1. 14 November, 22:07
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    4.454 N.

    Explanation:

    The force on a current carrying conductor in a magnetic field is given as,

    F = BILsinФ ... Equation 1

    Where F = magnetic Force, B = magnetic Field, I = current, L = Length of the wire, Ф = The angle between the conductor and the Field.

    Given: B = 0.289 T, I = 6.91 A, L = 6.7 m, Ф = 19°

    Substitute into equation 1

    F = 0.289 (6.91) (6.7) sin19

    F = 0.289*6.91*6.7*0.33

    F = 4.454 N.

    Hence the magnetic force = 4.454 N.
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