Ask Question
27 October, 13:33

In 1985 in San Antonio, Texas, an entire hotel building was moved several

blocks on 36 dollies. The mass of the building was about 1.45 x 10^6 kg. If

1.00 x 10² MJ of work was done to overcome the force of resistance that

was just 2.00 percent of the buildings weight, how far was the building

moved?

+4
Answers (1)
  1. 27 October, 17:17
    0
    The building was moved to a distance of, S = 510.2 m

    Explanation:

    Given data,

    The mass of the building, m = 1.45 x 10⁶ kg

    The work done to overcome the force of resistance, E = 1 x 10⁸ J

    The force of resistance of the building, 2% of building weight

    Fₓ = 2 x 1.45 x 10⁶ x 9.8 / 100

    = 284200 N

    The work done on the building,

    E = Fₓ · S

    ∴ S = E / Fₓ

    = 1.45 x 10⁶ / 284200 N

    = 510.2 m

    Hence, the building was moved to a distance of, S = 510.2 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In 1985 in San Antonio, Texas, an entire hotel building was moved several blocks on 36 dollies. The mass of the building was about 1.45 x ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers