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25 February, 10:17

The rigid link is supported by a pin at A and two A-36 steel wires, each having an unstretched length of 12 in. and cross-sectional area of 0.0125 in2. Determine the force developed in the wires when the link supports the vertical load of 350 lb.

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  1. 25 February, 12:55
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    Extension of the wire is not indicated

    Explanation:

    Young modulus (YM) = (stress/Strain); Tensile Stress/tensile Strain

    => YM * Strain = Stress=F/A; A is cross sectional area and F is the force

    (YM * Strain * A) / 36 = F (Force developed in each wire)

    F = (350 * e*0.0125) / 12
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