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18 June, 10:33

The distance between two telephone poles is 50 m. A 1 kg bird lands on the telephone wire midway between the poles, and the wire sags 0.2 m. How much tension does the bird produce in the wire

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  1. 18 June, 11:41
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    the tension produce by the bird in the wire is 610.3 N.

    Explanation:

    given information:

    mass of the bird, m = 1 kg

    distance of two telephone pole, L = 50 m

    wire sag, y = 0.2

    the tension of the wire can be calculate by the following equation

    tan θ = y / (L/2)

    = 0.2 / (50/2)

    = 0.2/25

    thus

    θ = arc tan (0.2/25)

    = 0.46°

    according to Newton's first law

    ΣF = 0, vertical direction

    T sin θ + T sin θ - mg = 0

    2 T sin θ = m g

    T = mg/2 sinθ

    = 1 x 9.8 / (2 sin 0.46)

    = 610.3 N
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