A bicyclist of mass 88.0 kg puts all his weight on each downward-moving pedal as he pedals up a steep road. Take the diameter of the circle in which the pedals rotate to be 0.33 m, and determine the magnitude of the maximum torque he exerts in the process.

Question

Physics

Gretchen

11 November, 02:35

A bicyclist of mass 88.0 kg puts all his weight on each downward-moving pedal as he pedals up a steep road. Take the diameter of the circle in which the pedals rotate to be 0.33 m, and determine the magnitude of the maximum torque he exerts in the process.

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Answers (1)

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Hector Cortez · Answer 1

142.296 Nm.

Explanation:

Torque: This is the force that tend to cause a body to rotate or twist. The S. I unit of torque is Nm.

From the question,

T = F*r ... Equation 1

Where T = Torque, F = Force, r = radius of the circle.

Note: F is the weight of the bicyclist.

Then,

F = W = mg ... Equation 2

Substitute equation 2 into equation 1

T = mgr ... Equation 3

Given: m = 88 kg, g = 9.8 m/s², r = 0.33/2 m

T = 88 (9.8) (0.33) / 2

T = 142.296 Nm.