A girl delivering newspapers covers her route by traveling 5.00 blocks west, 5.00 blocks north, and then 7.00 blocks east. What is her final position relative to her starting location?

P = 2i + 5j

Therefore she is 2 blocks east and 5 blocks north.

Resultant P = √ (2^2 + 5^2) = √ (4+25) = √29 = 5.4 blocks

Angle = taninverse (5/2)

Angle = 68.2°

Explanation:

Given:

Let west be negative and east be positive x axis.

Let north be the positive y axis.

5.00blocks west = - 5.00 i

5.00 blocks north = 5.00 j

7.00 blocks east = 7.00i

Addition of the vector form of hee position is;

P = - 5i + 7i - 5j

P = 2i + 5j

Therefore she is 2 blocks east and 5 blocks north.

Resultant P = √ (2^2 + 5^2) = √ (4+25) = √29 = 5.4 blocks

Angle = taninverse (5/2)

Angle = 68.2°