A stretch of 1 km new concrete pavement is being laid in a 100 mm thick layer. The ambient temperature when laying the concrete is 20°C, and you can assume that the concrete does not have any internal stress at this temperature. The thermal expansion coefficient of concrete is 10μm/m°C, and its elastic modulus is 20 GPa. Suppose all deformation of the concrete is restrained (the concrete cannot move), and suppose that the concrete behaves as a linear elastic material. Knowing its tensile strength is 10 MPa, at what temperature does this concrete crack?

Question

Physics

Eli

27 February, 11:16

A stretch of 1 km new concrete pavement is being laid in a 100 mm thick layer. The ambient temperature when laying the concrete is 20°C, and you can assume that the concrete does not have any internal stress at this temperature. The thermal expansion coefficient of concrete is 10μm/m°C, and its elastic modulus is 20 GPa. Suppose all deformation of the concrete is restrained (the concrete cannot move), and suppose that the concrete behaves as a linear elastic material. Knowing its tensile strength is 10 MPa, at what temperature does this concrete crack?

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Answers (1)

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Melissa · Answer 1

70 °C

Explanation:

Note : 1 GPA = 1000MPa; 1 μ = 10⁻⁶

Strain (∈) = δl / l = ∝ ΔT

Elastic modulus = Direct stress (strength) / Strain

20 * 10³ = 10 / ∝ ΔT

ΔT = 10 / 20 * 10³ ∝

= 10 / (20 * 10³ * 10⁻⁶)

= 10/0.02 = 50

= 50 °C

Therefore Temperature for concrete crack = ambient temperature + ΔT

20°C + 50 °C

= 70 °C