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27 January, 04:36

A player strikes a hockey puck giving it a velocity of 30.252 m/s. The puck slides across the ice for 0.267 s after which time its velocity is 28.452 m/s. The acceleration of gravity is 9.8 m/s 2. If the mass of the puck is 179 g, what is the average drag force exerted on it by the ice?

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  1. 27 January, 05:16
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    The average drag force is 1.206 (-i) N

    Explanation:

    You have to apply the equations of Impulse:

    I=FmedΔt

    Where I and Fmed (the average force) are vectors.

    The Impulse can also be expressed as the change in the quantity of motion (vector P)

    I=P2-P1

    P=mV (m is the mass and v is the velocity)

    You can calculate the quantity of motion at the beggining and at the end of the given time:

    Replace the mass in kg, dividing the mass by 1000 to convert it from g to kg.

    P1 = (0.179kg) (30.252m/s) i = 5.414 i kg. m/s

    P2=0.179kg) (28.452m/s) i = 5.092 i kg. m/s

    Where i is the unit vector in the x-direction.

    Therefore:

    I = 5.092 i - 5.414 i = - 0.322 i

    The average drag force is:

    Fmed = I/Δt = - 0.322 i / 0.267s = - 1.206 i N
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