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6 August, 13:34

A stone is thrown upward at an angle of 20◦ above the horizontal. Its maximum height during the trajectory is 41 m. The acceleration of gravity is 9.81 m/s 2. What was the stone's initial speed? Answer in units of m/s.

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  1. 6 August, 15:17
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    Stone's initial speed = 82.93 m/s

    Explanation:

    Consider the vertical motion of stone.

    We have equation of motion v² = u² + 2as

    At maximum height

    Final velocity, v = 0 m/s

    Acceleration, a = - 9.81 m/s²

    Displacement, s = 41 m

    Substituting

    v² = u² + 2as

    0² = u² + 2 x - 9.81 x 41

    u = 28.36 m/s

    We know that initial velocity in vertical motion is sin component of original initial speed.

    That is

    Initial speed x sin 20 = 28.36

    Initial speed = 82.93 m/s

    Stone's initial speed = 82.93 m/s
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