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11 November, 06:53

A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. Find the magnitude of the force on the wire if it carries a current of 2.3 A.

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  1. 11 November, 07:37
    0
    0.999 N.

    Explanation:

    From the question,

    The formula for the force on a conductor carrying current in a magnetic field is given as,

    F = BILsinФ ... Equation 1

    Where F = force on the wire, B = magnetic field, I = current carried by the wire, L = length of the wire, Ф = angle between the wire and the magnetic field.

    Given: B = 0.37 T, I = 2.3 A, L = 2 m, Ф = 30°

    Substitute into equation 1

    F = 0.37 (2.3) (2) (sin30)

    F = 0.37 (2.7) (2) (0.5)

    F = 0.999 N.

    Hence the force on the wire = 0.999 N.
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