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18 October, 11:18

A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 Nm. What is the angel (assumed to be less than 90 degrees) between the wrench handle and the direction the force is applied?

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  1. 18 October, 11:36
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    9.1°

    Explanation:

    Torque = distance from pivot * perpendicular force

    15 Nm = 0.5 m * perpendicular force

    perpendicular force = 30 N

    So the bertical component of the applied force that caused a turning effect (torque) was 30 N. Now we use this information to find the angle that would produce a vertical component of 30N from an applied force of 95 N.

    Fy = FSinθ

    15 = 95 Sinθ

    θ = 9.1°
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