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23 July, 02:12

A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 0.80 s apart. How far away did the impact occur? The speed of sound in air is 343 m/s, and in concrete is 3000 m/s.

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  1. 23 July, 03:21
    0
    309 m

    Explanation:

    time apart = 0.8 s

    speed of sound in air = 343 m/s

    speed of sound in concrete = 3000 m/s

    lets assume it time it takes to travel trough concrete = T

    the time it takes to travel through air = T + 0.8 since they are 0.8 s apart

    the distance traveled by both waves is the same, so we can equate the distance for both waves

    distance = speed x time

    for concrete, distance = 3000 x T for air, distance = 343 x (T + 0.8)

    now equating the two distance together we have

    3000 x T = 343 x (T + 0.8)

    3000T = 343T + 274.4

    3000T - 343T = 274.4

    T = 0.103 s

    recall that distance = 3000 x T = 3000 x 0.103 = 309 m
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