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5 January, 14:36

How much ethylene glycol (C2H6O2, the major component of antifreeze) must be added to 1 L of water to keep it from freezing at - 15 oC? Kf = 1.86 oC/m.

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  1. 5 January, 17:10
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    6.97 grams

    Explanation:

    T = m * Kf

    m (molality) = T/Kf

    T = - 15°C = - 15+273 = 258 K

    Kf = 1.86°C/m = 1.86°C/m * 1K/1°C = 1.86 K/m

    Molality = 258/1.86 = 138.71 mol/kg

    Mass of ethylene glycol = molality*mass of water in kilograms*molecular weight of ethylene glycol

    1 mole of water = 22.4 L

    1 L of water = 1/22.4 = 0.045 mol

    Mass of water = 0.045 mol * 18g/mol = 0.81 g = 0.81/1000 = 8.1*10^-4 kg

    Mass of ethylene glycol = 138.71*8.1*10^-4*62 = 6.97 grams
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