Ask Question
12 June, 03:49

A resistor rated at 250 k Ω is connected across two D cell batteries (each 1.50 V) in series, with a total voltage of 3.00 V. The manufacturer advertises that their resistors are within 5% of the rated value. What are the possible minimum current and maximum current through the resistor?

+3
Answers (1)
  1. 12 June, 07:16
    0
    Given Information:

    Resistance = R = 250 Ω

    Voltage = V = 3 V

    Tolerance = ±5%

    Required Information:

    Maximum current = Imax = ?

    Minimum current = Imin = ?

    Answer:

    Imax = 12.6 uA

    Imin = 11.4 uA

    Explanation:

    As we know from Ohm's law

    I = V/R

    The current will be maximum when R is minimum and the current will be minimum when R is maximum

    Rmax = 250,000 + 0.05*250,000

    Rmax = 250,000 + 12500

    Rmax = 262500 Ω

    Rmin = 250,000 - 0.05*250,000

    Rmin = 250,000 - 12500

    Rmin = 237500 Ω

    Imax = V/Rmin

    Imax = 3/237500

    Imax = 12.6 uA

    Imin = V/Rmax

    Imin = 3/262500

    Imin = 11.4 uA
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A resistor rated at 250 k Ω is connected across two D cell batteries (each 1.50 V) in series, with a total voltage of 3.00 V. The ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers