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9 February, 06:07

The planet Jupiter has a mass that is equal to 318 times Earth's mass, an orbital radius of 5.21 AU, and an orbital velocity of 13.1 km/s. Earth's orbital velocity is 29.8 km/s. What is the ratio of Jupiter's orbital angular momentum to that of Earth's?

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  1. 9 February, 09:42
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    Answer: 729

    Explanation:

    Mass of Jupiter / mass of earth = 318

    Velocity of Jupiter / velocity of earth = 13.1 / 29.8 = 0.440

    Orbital radius of Jupiter / orbital radius of earth = 5.21

    Angular momentum is given by;

    Am = mass * velocity * radius = mvr

    Therefore,

    Aj/Ae = 318*0.44*5.21 = 728.98

    Approximately = 729

    Goodluck
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