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1 April, 14:49

In another solar system is planet Driff, which

has 5 times the mass of the earth and also 5

times the radius.

How does the gravitational acceleration on

the surface of Driff compare to the gravita-

tional acceleration on the surface of the earth?

1. It's 15th as much.

2. There is no gravity on Driff because 5 times 4000 miles (the radius of the earth), is 20000 miles, far beyond the pull of gravity.

3. It's 125th as much.

4. It's 25 times as great.

5. It's 5 times as much.

6. It's the same, 10 m/s2

.

+3
Answers (1)
  1. 1 April, 16:37
    0
    It is (1/5) th as much.

    Explanation:

    If we apply the equation

    F = G*m*M / r²

    where

    m = mass of a man

    M₀ = mass of the planet Driff

    M = mass of the Earth

    r₀ = radius of the planet Driff

    r = radius of the Earth

    G = The gravitational constant

    F = The gravitational force on the Earth

    F₀ = The gravitational force on the planet Driff

    g = the gravitational acceleration on the surface of the earth

    g₀ = the gravitational acceleration on the surface of the planet Driff

    we have

    F₀ = G*m*M₀ / r₀² = G*m * (5*M) / (5*r) ²

    ⇒ F₀ = G*m*M / (5*r²) = (1/5) * F

    If

    F₀ = (1/5) * F

    then

    W₀ = (1/5) * W ⇒ m*g₀ = (1/5) * m*g ⇒ g₀ = (1/5) * g

    It is (1/5) th as much.
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