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15 May, 05:49

a street light is mounted at the top of a 15 foot pole. A man 6 ft tall walks away from the pole wit a speed of 7 ft/s along a straight path. How fast is the tip of his shadow moving when he is 40 ft from the pole

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  1. 15 May, 08:55
    0
    16.3 ft/s

    Explanation:

    Let d=distance

    and

    x = length of shadow.

    Therfore,

    x = (d + x)

    = 6/15

    So,

    15x = 6x + 6d

    9x = 6d.

    x = (2/3) d.

    As we know that:

    dx=dt

    = (2/3) (d/dt)

    Also,

    Given:

    d (d) = dt

    = 7 ft/s

    Thus,

    d (d + x) = dt

    = (7/3) d (d/dt)

    Substitute, d = 7

    d (d + x) = 49/3 ft/s.

    Hence,

    d (d + x) = 16.3 ft/s.
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