You are pushing a crate horizontally with 100 N across a 10 m factory floor. If the force of friction on the crate is a steady 70 N, how much kinetic energy is gained by the crate

K E = 300 J

Explanation:

given,

Force of pushing crate, F = 100 N

distance of push = 10 m

frictional force = 70 N

kinetic energy is gained by the crate = ?

using work energy theorem

K E = work done

K E = F. s

K E = (100 - 70) x 10

K E = 30 x 10

K E = 300 J

kinetic energy is gained by the crate is equal to 300 J.