Particle A has half the mass and eight times the kinetic energy of particle B. What is the speed ratio vA / vB?

Use the equation "KE=½mv²", and use some algebra. > "Particle A has two times the mass ... of particle B" mA = 2mB > "Particle A has ... 8 situations the kinetic power of particle B" KE_A = 8 (KE_B) or: ½ (mA) (vA) ² = 8 (½ (mB) (vB) ²) the rest is uncomplicated algebra: in basic terms sparkling up the above equation for "vA/vB". (hint: start up by utilising dividing the two factors by utilising " (mB) (vB) ²". Then make the substitution: mA/mB = 2 (from the 1st eq0.5 ma * VA^2 = 8 * 0.5 * mb * VB^2

0.5 * 0.5*mb * VA^2 = 8 * 0.5 * mb * VB^2

0.5 * 0.5 * VA^2 = 8 * 0.5 * VB^2

VA/VB = 4uation))