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15 May, 15:03

A string pulls a 9 kg box horizontally across a table with a force of 50 N. the box has a coefficient of friction with the table of 0.45. what is the net force of the box?

A. 90 N

B. 40 N

C. 50 N

D. 10 N

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Answers (1)
  1. 15 May, 18:59
    0
    D. 10 N

    Explanation:

    Draw a free body diagram of the box. There are four forces:

    Normal force N pushing up.

    Weight force mg pulling down.

    Applied force P to the right.

    Friction force Nμ to the left.

    Sum of forces in the y direction:

    ∑F = ma

    N - mg = 0

    N = mg

    Sum of forces in the x direction:

    ∑F = P - Nμ

    ∑F = P - mgμ

    ∑F = (50 N) - (9 kg) (9.8 m/s²) (0.45)

    ∑F ≈ 10 N
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