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19 June, 13:13

A water molecule perpendicular to an electric field has 1.40*10-21 J more potential energy than a water molecule aligned with the field. The dipole moment of a water molecule is 6.2*10-30Cm.

What is the strength of the electric field?

Express your answer with the appropriate units.

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  1. 19 June, 14:54
    0
    The strength of the electric field is 2.258 x 10⁸ N/C

    Explanation:

    Potential energy = - p*ECosθ

    where;

    d is the dipole moment

    E is the electric field

    θ is the angle of inclination

    →When the water molecules is perpendicular to the field, θ = 90° and potential energy = p*ECosθ = d*ECos0 = 0

    Total potential energy = 0 + 1.40*10⁻²¹J, since it is 1.40*10⁻²¹J more

    →When the water molecules is aligned to the field, θ = 0°

    potential energy = - p*ECosθ

    dipole moment, p = 6.2*10⁻³⁰Cm

    = - (6.2*10⁻³⁰) * (E) Cos0

    0 + 1.40*10⁻²¹ J = - (6.2*10⁻³⁰) * (E),

    E = (1.40*10⁻²¹ J) / (6.2*10⁻³⁰)

    E = 2.258 x 10⁸ N/C

    Therefore, the strength of the electric field is 2.258 x 10⁸ N/C
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