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15 May, 04:42

A system does 203 J of work on its environment and gains 96.8 J of heat in the process. Find the change in the internal energy of (a) the system and (b) the environment.

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  1. 15 May, 07:06
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    a) The change in the internal energy of the system = - 106.2 J

    b) The change in the internal energy of the environment = 106.2 J

    Explanation:

    Given that

    The work done by system, W = 203 J

    Heat gain, Q = 96.8 J

    We know that

    Q = W + ΔU

    ΔU = Change in the internal energy

    W=Work done

    Q=Heat

    Now by putting the values in the above equation we get

    96.8 = 203 + ΔU

    ΔU = 96.8 - 203 J

    ΔU = - 106.2 J

    The change in the internal energy of the system = - 106.2 J

    The change in the internal energy of the environment = 106.2 J
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