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11 September, 09:12

Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20*106 volts per meter. Part A Compute the magnitude of the charge per unit area σ on the conducting plate. Express your answer in coulombs per square meter to three significant figures.

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  1. 11 September, 12:47
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    Answer: 38.2 μC

    Explanation: In order to solve this problem we have to use the relationship for a two plate capacitor with a dielectric so:

    C = Q/V = we also know that for two paralel plates C=εo*k*A/d and V=E/d

    where k is the dielectric constant, A plate area, V is potential difference; E electric field and d the separation between the plates.

    reorganizing we have:

    Q/A=σ = E*k/εo = 1.2 * 10^6*3.6/8.85 * 10^-12=38.2μC
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