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25 March, 18:19

A 6-inch diameter smooth plastic pipe 3100 ft in length delivers 2.2 cfs of water between two reservoirs. Water viscosity is 11.11 x 10-6 ft2/s. What is the elevation difference (ft) in water surface between the reservoirs

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  1. 25 March, 22:12
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    h = 6.39 m

    Explanation:

    radius = 6/2 = 3in = 3/12 in/ft = 0.25 ft

    apply continuity equation to evaluate the velocity

    flow rate = area * velocity

    2.2 = π (0.25^2) * V

    ⇒ V = 11.2 ft/s

    *assuming there is no applied pressure difference along the pipe

    applying Energy conservation law

    initial potential energy = final kinetic energy

    pgh = (1/2) * pv^2

    where p = density

    v = velocity

    plugging in the values:

    p cancels out on both the sides

    ⇒ 9.81 * h = (11.2^2) / 2

    h = 6.39 m
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