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7 December, 06:02

A particle moves along the x-axis with velocity given by v (t) = 3t2+6t for time tâ¥0. If the particle at position x=2 at time t=0, what is the position of the particle at time t=1?

a) 4

b) 6

c) 0

d) 11

e) 12

+1
Answers (2)
  1. 7 December, 06:41
    0
    The answer is B) 6

    Explanation:

    because im smrt
  2. 7 December, 07:47
    0
    b) 6

    Explanation:

    Given

    v (t) = 3t²+6t

    X (0) = 2

    X (1) = ?

    Knowing that

    v (t) = 3t²+6t = dX/dt

    ⇒ ∫dX = ∫ (3t²+6t) dt

    ⇒ X - X₀ = t³ + 3t²

    ⇒ X (t) = X₀ + t³ + 3t²

    If X (0) = 2

    ⇒ X (0) = X₀ + (0) ³ + 3 (0) ² = 2

    ⇒ X₀ = 2

    then we have

    X (t) = t³ + 3t² + 2

    when

    t = 1

    X (1) = (1) ³ + 3 (1) ² + 2

    X (1) = 6
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