A particle moves along the x-axis with velocity given by v (t) = 3t2+6t for time tâ¥0. If the particle at position x=2 at time t=0, what is the position of the particle at time t=1?

a) 4

b) 6

c) 0

d) 11

e) 12

Question

Physics

Guest

7 December, 06:02

A particle moves along the x-axis with velocity given by v (t) = 3t2+6t for time tâ¥0. If the particle at position x=2 at time t=0, what is the position of the particle at time t=1?

a) 4

b) 6

c) 0

d) 11

e) 12

+1

Answers (2)

Know the Answer?

Pugh · Answer 1

The answer is B) 6

Explanation:

because im smrt

Pedro · Answer 2

b) 6

Explanation:

Given

v (t) = 3t²+6t

X (0) = 2

X (1) = ?

Knowing that

v (t) = 3t²+6t = dX/dt

⇒ ∫dX = ∫ (3t²+6t) dt

⇒ X - X₀ = t³ + 3t²

⇒ X (t) = X₀ + t³ + 3t²

If X (0) = 2

⇒ X (0) = X₀ + (0) ³ + 3 (0) ² = 2

⇒ X₀ = 2

then we have

X (t) = t³ + 3t² + 2

when

t = 1

X (1) = (1) ³ + 3 (1) ² + 2

X (1) = 6

A particle moves along the x-axis with velocity given by v (t) = 3t2+6t for time tâ¥0. If the particle at position x=2 at time t=0, what is the position of the particle at time t=1?a) 4b) 6c) 0d) 11e) 12

A particle moves along the x-axis with velocity given by v (t) = 3t2+6t for time tâ¥0. If the particle at position x=2 at time t=0, what is the position of the particle at time t=1?

a) 4

b) 6

c) 0

d) 11

e) 12